(2x+2)^2+2=18

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Solution for (2x+2)^2+2=18 equation: 



(2x+2)^2+2=18

We move all terms to the left:

(2x+2)^2+2-(18)=0

We add all the numbers together, and all the variables

(2x+2)^2-16=0

We move all terms containing x to the left, all other terms to the right

(2x+2)^2=16

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